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प्रश्न
In figure, a body A of mass m slides on plane inclined at angle θ1 to the horizontal and µ1 is the coefficent of friction between A and the plane. A is connected by a light string passing over a frictionless pulley to another body B, also of mass m, sliding on a frictionless plane inclined at angle θ2 to the horizontal. Which of the following statements are true?
- A will never move up the plane.
- A will just start moving up the plane when `µ = (sin θ_2 - sin θ_1)/(cos θ_1)`
- For A to move up the plane, θ2 must always be greater than θ1.
- B will always slide down with constant speed.
उत्तर
b and c
Explanation:
This system can be represented by the figure given below.
Here we have `f = μmg cos θ_1`
Now, body A will move up and body B will move down the plane,
If `mg sin θ_1 + f = mg sin θ_2`
That gives us, `mg sin θ_1 + μmg cos θ_1 = mg sin θ_2`
Or, `μ cos θ_1 = sin θ_2 - sin θ_1`
Hence, `μ = s (hati nθ_2 - sin θ_1)/(cos θ_1)`
Also, body A will move down and body B will move up the plane,
If `mg sin θ_2 - mg sin θ_1 > 0`
Or, `sin θ_2 > sin θ_1`
Hence, θ2 > θ1.
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