Question

In H₂–O₂ fuel cell, the reaction taking place at negative electrode is:

विकल्प

• \[\ce{2H2_{(g)} + 4OH^-_{( aq)} -> 4H2O_{(l)} + 4e^-}\]

• \[\ce{4OH^-_{( aq)} -> O2_{(g)} + 2H2O_{(l)} + 4e^-}\]

• \[\ce{2H2_{(g)} + 2OH^-_{( aq)} -> 2H2O_{(l)} + 2e^-}\]

• \[\ce{O2_{(g)} + 2H2O_{(l)} -> 4OH^-_{( aq)}}\]

Answer 1

\[\ce{2H2_{(g)} + 4OH^-_{( aq)} -> 4H2O_{(l)} + 4e^-}\]