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Question
In H2–O2 fuel cell, the reaction taking place at negative electrode is:
Options
\[\ce{2H2_{(g)} + 4OH^-_{( aq)} -> 4H2O_{(l)} + 4e^-}\]
\[\ce{4OH^-_{( aq)} -> O2_{(g)} + 2H2O_{(l)} + 4e^-}\]
\[\ce{2H2_{(g)} + 2OH^-_{( aq)} -> 2H2O_{(l)} + 2e^-}\]
\[\ce{O2_{(g)} + 2H2O_{(l)} -> 4OH^-_{( aq)}}\]
MCQ
Solution
\[\ce{2H2_{(g)} + 4OH^-_{( aq)} -> 4H2O_{(l)} + 4e^-}\]
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