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प्रश्न
In LCR series circuit, the condition for current resonance is ______.
विकल्प
ωL =`1/(omega"C")`
ωL = ωC
`f=1/(2pi"LC")`
`f=2pi"LC"`
MCQ
रिक्त स्थान भरें
उत्तर
In LCR series circuit, the condition for current resonance is `bbunderline(omega"L"=1/(omega"C"))`.
shaalaa.com
Electric Resonance
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
