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Question
In LCR series circuit, the condition for current resonance is ______.
Options
ωL =`1/(omega"C")`
ωL = ωC
`f=1/(2pi"LC")`
`f=2pi"LC"`
MCQ
Fill in the Blanks
Solution
In LCR series circuit, the condition for current resonance is `bbunderline(omega"L"=1/(omega"C"))`.
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Electric Resonance
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