Advertisements
Advertisements
प्रश्न
In ∆LMN, l(LM) = 6.2 cm, m∠LMN = 60°, l(MN) = 4 cm. Construct ∆LMN.
उत्तर
Steps of construction:
(1) Draw seg LM of length 6.2 cm.
(2) Draw ray MA such that ∠LMA = 60°.
(3) Draw an arc of 4 cm from the vertex M, cutting the ray MA at N.
Therefore, △LMN is the required triangle.
संबंधित प्रश्न
In ΔABC, l(AB) = 5.5 cm, l(BC) = 4.2 cm, l(AC) = 3.5 cm
In ∆ STU, l(ST) = 7 cm, l(TU) = 4 cm, l(SU) = 5 cm
Draw an equilateral triangle with side 6.5 cm.
Draw triangle with the measures given below.
In ∆FUN, l(FU) = 5 cm, l(UN) = 4.6 cm, m∠U = 110°
Construct a triangle using the given data: BC = 6cm, AC = 5.0cm and ∠C = 60°
Construct a right-angled triangle in which Side DE = 6 cm and ∠E = 30°, ∠D = 90°
Construct an isosceles triangle in which: PQ = QR, PR = 4.5 cm and ∠R = 60°
Construct an equilateral triangle using the given data: Altitude AD = 5 cm
Construct a triangle using the following data: DE + EF = 10.3 cm, EF = 6.4 cm and ∠E = 75°
Construct a triangle using the given data: XY - XZ = 1.5 cm, YZ = 3.4 cm and ∠X = 45°
