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प्रश्न
In a simultaneous throw of a pair of dice, find the probability of getting a doublet of odd numbers
उत्तर
In a throw of pair of dice, total no of possible outcomes = 36 (6 × 6) which are
(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)
(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)
(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)
(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)
(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)
(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)
E ⟶ event of getting a doublet of odd no’s
No. of favorable outcomes = 3 {(1, 1) (3, 3) (5, 5)}
Total no. of possible outcomes = 36
We know that, Probability P(E) =`"No.of favorable outcomes"/"Total no.of possible outcomes"`
P(E) =3/36 =1/12
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