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In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound. - Chemistry

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प्रश्न

In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound.

संख्यात्मक

उत्तर

Total mass of organic compound = 0.468 g [Given]

Mass of barium sulphate formed = 0.668 g [Given]

1 mol of BaSO4 = 233 g of BaSO4 = 32 g of sulphur

Thus, 0.668 g of BaSO4 contains

= `(32xx0.668)/233` g of sulphur

= 0.0917 g of sulphur

Therefore, percentage of sulphur

= `0.0917/0.468 xx 100` =  19.59%

Hence, the percentage of sulphur in the given compound is 19.59%.

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Quantitative Analysis of Halogens
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Organic Chemistry - Some Basic Principles and Techniques - EXERCISES [पृष्ठ ३७२]

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एनसीईआरटी Chemistry - Part 1 and 2 [English] Class 11
अध्याय 12 Organic Chemistry - Some Basic Principles and Techniques
EXERCISES | Q 12.35 | पृष्ठ ३७२
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