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Question
In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound.
Solution
Total mass of organic compound = 0.468 g [Given]
Mass of barium sulphate formed = 0.668 g [Given]
1 mol of BaSO4 = 233 g of BaSO4 = 32 g of sulphur
Thus, 0.668 g of BaSO4 contains
= `(32xx0.668)/233` g of sulphur
= 0.0917 g of sulphur
Therefore, percentage of sulphur
= `0.0917/0.468 xx 100` = 19.59%
Hence, the percentage of sulphur in the given compound is 19.59%.
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