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प्रश्न
In the figure given below, if AC = AD = CD = BD; find angle ABC.
योग
उत्तर
In ΔACD,
AC = AD = CD ......[Given]
Hence, ACD is an equilateral triangle.
∴ ∠ACD = ∠CDA = ∠CAD = 60°
In ΔADB
AD = DB
∠DAB = ∠ABD = Let x
x + x + 120° = 180°
`x = (180° - 120°)/2`
= 30°
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