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प्रश्न
In the figure, PQRS is a square with side 10 cm. The sectors drawn with P and R as centres form the shaded figure. Find the area of the shaded figure. (Use π = 3.14)
योग
उत्तर
Sides of square = 10 cm
Radius of quadrant SEQR = 10 cm
∴ Area = `1/4` πr2
= `1/4 xx 22/7 xx 10 xx 10`
= 78.57 cm2
Area of triangle SQR = `1/2 xx QR xx SR`
= `1/2 xx 10 xx 10`
= 50 cm2
Area of segment SEQ = Area of quadrant SEQR – Area of ΔSQR
= 78·57 – 50
= 28.57 cm2
Total area of shaded portion = 2 × 28.57 = 57.14 cm2
As a result, the shaded portion's area is 57.14 cm2.
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