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प्रश्न
In the given progressive wave y = 5 sin (100 πt – 0.4 πx) where y and x are in m, t is in s. What is the amplitude.
उत्तर
Wave is travelling in + x direction because ωt and kx have opposite signs.
The standard equation is given by, y = a sin(ωt – kx + `phi`)
We have, y = 5 sin(100 πt – 0.04 πx)
Therefore, on comparing we get a = 5 m, ω = 100 π, k = 0.4 π
Amplitude, a = 5 m.
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