Question

In the redox reaction, \[\ce{2MnO^-_4 + SO^{2-}_3 + H2O -> 2MnO^{2-}_4 + SO^{2-}_4 + 2H^+}\], the reductant is:

विकल्प

• \[\ce{MnO^-_4}\]

• \[\ce{SO^{2-}_3}\]

• \[\ce{H2O}\]

• \[\ce{H^+}\]

Answer 1

\[\ce{SO^{2-}_3}\]

Explanation:

The oxidation number of 'S' is increased from +4 to +6. Therefore, \[\ce{SO^{2-}_3}\] is the reducing agent/reductant.