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In the table given below, class-mark and frequencies are given. Construct the frequency table taking inclusive and exclusive classes. Class width 5 15 25 35  Frequency 3 9 15 13 - Algebra

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प्रश्न

In the table given below, class-mark and frequencies are given. Construct the frequency table taking inclusive and exclusive classes.

Class width  Frequency
5 3
15 9
25 15
35 13
योग

उत्तर

Suppose, the lower limit of the  5 classes is x1 and the upper limit is x2.

Class mark = `("Lower class limit" + "Upper class limit")/2`

5 = `(x_1 + x_2)/2`

∴ x1 + x2 = 10   ...(1)

The difference between the classes of two adjacent classes is equal to the class width of each class.

∴ class width = 15 − 5 = 25 − 15 = 10

∴ x2 + x1 = 10

∴ − x1 + x2 = 10   ...(2)

Let's sum the equations (1) and (2).

      x1 + x2 = 10
+ − x1 + x2 = 10
___________________
           2x2 = 20

∴ x2 = 10

The value of x2 = 10 is put into equation (1)

x1 + 10 = 10

∴ x1 = 10 − 10

∴ x1 = 0

∴ First-class = 0 − 10. From this the next class are 10 − 20, 20 − 30 and 30 − 40.

So, the exclusive frequency table is given by:

Exclusive class  Classmark  Frequency
0 − 10 5 3
10 − 20 15 9
20 − 30  25 15
30 − 40 35 13

class width = Upper limit − Lower limit

= 10 − 0 = 10

Also, the inclusive frequency table is given by:

Inclusive class  Classmark  Frequency
0.5 − 9.5 5 3
10.5 − 19.5 15 9
20.5 − 29.5 25 15
30.5 − 39.5 35 13
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अध्याय 7: Statistics - Practice set 7.3 [पृष्ठ ११९]

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बालभारती Algebra (Mathematics 1) [English] 9 Standard Maharashtra State Board
अध्याय 7 Statistics
Practice set 7.3 | Q (7) (i) | पृष्ठ ११९

संबंधित प्रश्न

In a school, 46 students of 9th standard, were told to measure the lengths of the pencils in their compass boxes in centimeters. The data collected was as follows.

16, 15, 7, 4.5, 8.5, 5.5, 5, 6.5, 6, 10, 12, 13, 4.5, 4.9, 16, 11, 9.2, 7.3, 11.4, 12.7, 13.9, 16, 5.5, 9.9, 8.4, 11.4, 13.1, 15, 4.8, 10, 7.5, 8.5, 6.5, 7.2, 4.5, 5.7, 16, 5.7, 6.9, 8.9, 9.2, 10.2, 12.3, 13.7, 14.5, 10.

By taking inclusive classes 0-5, 5-10, 10-15.... prepare a grouped frequency distribution table.


Construct a cumulative frequency distribution table from the frequency table given below:
( i )

Class Interval Frequency
0 - 8  9
8 - 16  13
16 - 24  12
24 - 32  7
32 - 40  15

( ii )

Class Interval  Frequency 
1 - 10  12
11 - 20 18
21 - 30 23
31 - 40 15
41 - 50 10

In a certain colony, there are 50 families. The number of people in every family is given below. Draw up the frequency table.
5, 4, 5, 4, 5, 3, 3, 3, 4, 3, 4, 2, 3, 4, 2, 2, 2, 2, 4, 5, 1, 3, 2, 4, 5, 3, 3, 2, 4, 4, 2, 3, 4, 3, 4, 2, 3, 4, 5, 3, 2, 3, 2, 3, 4, 5, 3, 2, 3, 2


The upper limit of the class interval (25 - 35) is _____________


In the class interval 26 – 33, 33 is known as ______.


The difference between the upper and lower limit of a class interval is called the ______ of the class interval.


In the class intervals 10 – 20, 20 – 30, etc., respectively, 20 lies in the class ______.


If the fifth class interval is 60 – 65, fourth class interval is 55 – 60, then the first-class interval is 45 – 50.


The marks obtained (out of 20) by 30 students of a class in a test are as follows:

14, 16, 15, 11, 15, 14, 13, 16, 8, 10, 7, 11, 18, 15, 14, 19, 20, 7, 10, 13, 12, 14, 15, 13, 16, 17, 14, 11, 10, 20.

Prepare a frequency distribution table for the above data using class intervals of equal width in which one class interval is 4 – 8 (excluding 8 and including 4).


Construct a frequency distribution table for the following weights (in grams) of 35 mangoes, using the equal class intervals, one of them is 40 – 45 (45 not included).

30, 40, 45, 32, 43, 50, 55, 62, 70, 70, 61, 62, 53, 52, 50, 42, 35, 37, 53, 55, 65, 70, 73, 74, 45, 46, 58, 59, 60, 62, 74, 34, 35, 70, 68.

  1. How many classes are there in the frequency distribution table?
  2. Which weight group has the highest frequency?

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