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Question
In the table given below, class-mark and frequencies are given. Construct the frequency table taking inclusive and exclusive classes.
Class width | Frequency |
5 | 3 |
15 | 9 |
25 | 15 |
35 | 13 |
Solution
Suppose, the lower limit of the 5 classes is x1 and the upper limit is x2.
Class mark = `("Lower class limit" + "Upper class limit")/2`
5 = `(x_1 + x_2)/2`
∴ x1 + x2 = 10 ...(1)
The difference between the classes of two adjacent classes is equal to the class width of each class.
∴ class width = 15 − 5 = 25 − 15 = 10
∴ x2 + x1 = 10
∴ − x1 + x2 = 10 ...(2)
Let's sum the equations (1) and (2).
x1 + x2 = 10
+ − x1 + x2 = 10
___________________
2x2 = 20
∴ x2 = 10
The value of x2 = 10 is put into equation (1)
x1 + 10 = 10
∴ x1 = 10 − 10
∴ x1 = 0
∴ First-class = 0 − 10. From this the next class are 10 − 20, 20 − 30 and 30 − 40.
So, the exclusive frequency table is given by:
Exclusive class | Classmark | Frequency |
0 − 10 | 5 | 3 |
10 − 20 | 15 | 9 |
20 − 30 | 25 | 15 |
30 − 40 | 35 | 13 |
class width = Upper limit − Lower limit
= 10 − 0 = 10
Also, the inclusive frequency table is given by:
Inclusive class | Classmark | Frequency |
0.5 − 9.5 | 5 | 3 |
10.5 − 19.5 | 15 | 9 |
20.5 − 29.5 | 25 | 15 |
30.5 − 39.5 | 35 | 13 |
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