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प्रश्न
In triangle ABC, AB > AC and D is a point inside BC.
Show that: AB > AD.
उत्तर
Given that, AB > AC
⇒ ∠C > ∠B ...(i)
Also in ΔADC
∠ADB = ∠DAC + ∠C ...[ Exterior angle ]
⇒ ∠ADB > ∠C
⇒ ∠ADB > ∠C > ∠B ...[ From(i) ]
⇒ ∠ADB > ∠B
⇒ AB > AD.
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