Advertisements
Advertisements
प्रश्न
Is x = 5 a solution of the quadratic equation x2 – 2x – 15 = 0?
उत्तर
x2 – 2x – 15 = 0
For x = 5 to be solution of the given quadratic equation it should satisfy the equation.
So, substituting x = 5 in the given equation, we get
L.H.S = (5)2 – 2(5) – 15
= 25 – 10 – 15
= 0
= R.H.S
Hence, x = 5 is a solution of the quadratic equation x2 – 2x – 15 = 0.
APPEARS IN
संबंधित प्रश्न
Solve `9/2 x = 5 + x^2`
Use the substitution y = 2x + 3 to solve for x, if` 4 (2x + 3)^2 − (2x + 3) − 14 = 0 `
`6x^2+11x+3=0`
`2x^2-x+1/8=0`
` x^2+6x-(a^2+2a-8)=0`
Write the following equation in the form ax2 + bx + c = 0, then write the values of a, b, c for the equation.
2y = 10 – y2
Find the value of k for which the equation 3x2 – 6x + k = 0 has distinct and real roots.
Determine whether x = -1 is a root of the equation x2 - 3x +2=0 or not.
Check whether the following are quadratic equations: `x^2 + (1)/(x^2) = 3, x ≠ 0`
The sum of the reciprocals of Varun's age (in years) 3 years ago and 5 years from now is `1/3`. Find his present age.