Advertisements
Advertisements
प्रश्न
`6x^2+11x+3=0`
उत्तर
Given
`6x^2+11x+3=0`
`⇒6x^2+9x+2x+3=0`
`⇒3x(2x+3)+1(2x+3)=0`
`⇒(3x+1)(2x+3)=0`
`⇒3x+1=0 or 2x+3=0`
`⇒x=-1/3 or x=-3/2`
Hence, `-1/3 and -3/2 `are the roots of the equation `6x^2+11x+3=0`
APPEARS IN
संबंधित प्रश्न
Check whether the following is the quadratic equation:
(x + 2)3 = 2x(x2 - 1)
Solve the following equation for x and give, in the following case, your answer correct to one decimal place:
x2 – 8x + 5 = 0
Solve the following equation for x and give, in the following case, your answer correct to 2 decimal places:
`4x + 6/x + 13 = 0`
Solve the following equation using the formula:
`(x - 1)/(x - 2) + (x - 3)/(x - 4) = 3 1/3`
Without solving comment upon the nature of roots of each of the following equations:
`"x"^2 – "ax" – "b"^2 = 0`
`x^2-(1+sqrt2)x+sqrt2=0`
`4x^2+4bx-(a^2-b^2)=0`
`abx^2+(b^2-ac)x-bc=0`
Find which of the following equations are quadratic:
(x – 4)(3x + 1) = (3x – 1)(x + 2)
Solve the following equation by using formula :
a (x2 + 1) = (a2+ 1) x , a ≠ 0
