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प्रश्न
`6x^2+x--12=0`
उत्तर
Given:
`6x^2+x-12=0`
`⇒ 6x^2+9x-8x-12=0`
`⇒3x(2x+3)-4(2x+3)=0`
`⇒(3x-4)(2x+3)=0`
`⇒3x-4=0 or 2x+3=0`
`⇒x=4/3 or x=-3/2`
Hence,` 4/3 and -3/2` are the root equation `6x^2+x-12=0`
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