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प्रश्न
`6x^2+11x+3=0`
उत्तर
Given
`6x^2+11x+3=0`
`⇒6x^2+9x+2x+3=0`
`⇒3x(2x+3)+1(2x+3)=0`
`⇒(3x+1)(2x+3)=0`
`⇒3x+1=0 or 2x+3=0`
`⇒x=-1/3 or x=-3/2`
Hence, `-1/3 and -3/2 `are the roots of the equation `6x^2+11x+3=0`
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