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प्रश्न
`abx^2+(b^2-ac)x-bc=0`
उत्तर
`abx^2+(b^2-ac)x-bc=0`
⇒`abx^2+b^2x-acx-bc=0`
⇒`bx(ax+b)-c(ax+b)=0`
⇒`(bx-c)(ax+b)=0`
⇒`bx-c=0 or ax+b=0`
⇒`x=c/b or x=-b/a`
Hence, the roots of the equation are `c/b ` and `-b/a`
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