Advertisements
Advertisements
Question
`abx^2+(b^2-ac)x-bc=0`
Solution
`abx^2+(b^2-ac)x-bc=0`
⇒`abx^2+b^2x-acx-bc=0`
⇒`bx(ax+b)-c(ax+b)=0`
⇒`(bx-c)(ax+b)=0`
⇒`bx-c=0 or ax+b=0`
⇒`x=c/b or x=-b/a`
Hence, the roots of the equation are `c/b ` and `-b/a`
APPEARS IN
RELATED QUESTIONS
Check whether the following is the quadratic equation:
(x + 2)3 = 2x(x2 - 1)
Find the value of ‘m’, if the following equation has equal roots:
(m – 2)x2 – (5 + m)x + 16 = 0
Solve the following equation using the formula:
`(2x + 3)/(x + 3) = (x + 4)/(x + 2)`
Which of the following are quadratic equation in x?
`sqrt2x^2+7x+5sqrt2`
`2x^2-x+1/8=0`
`4^((x+1))+4^((1-x))=10`
If -1 and 3 are the roots of x2+px+q=0
then find the values of p and q
In each of the following, determine whether the given numbers are solutions of the given equation or not: `x^2 - sqrt(2)x - 4 = 0, x = -sqrt(2),2sqrt(2)`
Solve the following equation by using formula :
`(1)/x + (1)/(x - 2) = 3, x ≠ 0, 2`
Solve the following equation by using formula :
`(3x - 4)/(7) + (7)/(3x - 4) = (5)/(2), x ≠ (4)/(3)`
