Advertisements
Advertisements
प्रश्न
Let f: A → B be a function defined by f(x) = `x/2` – 1, where A = {2, 4, 6, 10, 12}, B = {0, 1, 2, 4, 5, 9}. Represent f by an arrow diagram
उत्तर
A = {2, 4, 6, 10, 12}
B = {0, 1, 2, 4, 5, 9}
f(x) = `x/(2) - 1`
f(2) = `(2)/(2) - 1` = 1 – 1 = 0
f(4) = `(4)/(2) - 1` = 2 – 1 = 1
f(6) = `(6)/(2) - 1` = 3 – 1 = 2
f(10) = `(10)/(2) - 1` = 5 – 1 = 4
f(12) = `(12)/(2) - 1` = 6 – 1 = 5
Arrow diagram
APPEARS IN
संबंधित प्रश्न
Determine whether the graph given below represent function. Give reason for your answer concerning graph
Determine whether the graph given below represent function. Give reason for your answer concerning graph
Determine whether the graph given below represent function. Give reason for your answer concerning graph
Determine whether the graph given below represent function. Give reason for your answer concerning graph
Let f: A → B be a function defined by f(x) = `x/2` – 1, where A = {2, 4, 6, 10, 12}, B = {0, 1, 2, 4, 5, 9}. Represent f by set of ordered pairs
Let f: A → B be a function defined by f(x) = `x/2` – 1, where A = {2, 4, 6, 10, 12}, B = {0, 1, 2, 4, 5, 9}. Represent f by a table
Represent the function f = {(1, 2), (2, 2), (3, 2), (4, 3), (5, 4)} through an arrow diagram
Represent the function f = {(1, 2), (2, 2), (3, 2), (4, 3), (5, 4)} through a table form
Represent the function f = {(1, 2), (2, 2), (3, 2), (4, 3), (5, 4)} through a graph
Given that f(x) = `{{:(sqrt(x - 1), x ≥ 1),(4, x < 1):}` Find f(a + 1) in terms of a. (Given that a ≥ 0)
