Advertisements
Advertisements
प्रश्न
Let f: A → B be a function defined by f(x) = `x/2` – 1, where A = {2, 4, 6, 10, 12}, B = {0, 1, 2, 4, 5, 9}. Represent f by set of ordered pairs
उत्तर
A = {2, 4, 6, 10, 12}
B = {0, 1, 2, 4, 5, 9}
f(x) = `x/(2) - 1`
f(2) = `(2)/(2) - 1` = 1 – 1 = 0
f(4) = `(4)/(2) - 1` = 2 – 1 = 1
f(6) = `(6)/(2) - 1` = 3 – 1 = 2
f(10) = `(10)/(2) - 1` = 5 – 1 = 4
f(12) = `(12)/(2) - 1` = 6 – 1 = 5
Set of ordered pairs
f = {(2, 0) (4, 1) (6, 2) (10, 4) (12, 5)}
APPEARS IN
संबंधित प्रश्न
Determine whether the graph given below represent function. Give reason for your answer concerning graph
Determine whether the graph given below represent function. Give reason for your answer concerning graph
Determine whether the graph given below represent function. Give reason for your answer concerning graph
Let f: A → B be a function defined by f(x) = `x/2` – 1, where A = {2, 4, 6, 10, 12}, B = {0, 1, 2, 4, 5, 9}. Represent f by a table
Let f: A → B be a function defined by f(x) = `x/2` – 1, where A = {2, 4, 6, 10, 12}, B = {0, 1, 2, 4, 5, 9}. Represent f by an arrow diagram
Represent the function f = {(1, 2), (2, 2), (3, 2), (4, 3), (5, 4)} through a table form
Represent the function f = {(1, 2), (2, 2), (3, 2), (4, 3), (5, 4)} through a graph
Multiple choice question :
f(x) = (x + 1)3 – (x – 1)3 represent a function which is
Given that f(x) = `{{:(sqrt(x - 1), x ≥ 1),(4, x < 1):}` Find f(0)
Given that f(x) = `{{:(sqrt(x - 1), x ≥ 1),(4, x < 1):}` Find f(a + 1) in terms of a. (Given that a ≥ 0)