Advertisements
Advertisements
प्रश्न
Let y = `f(x)` be the equation of a curve. Then the equation of tangent at (xo, yo) is :-
विकल्प
`y - y_o = m(x - x_o)`
`y_o - y = m(x_o - x)`
`x_o - x = m(y - y_o)`
`x - x_o = m(y_o - y)`
MCQ
उत्तर
`y - y_o = m(x - x_o)`
Explanation:
Tangent to a Curve:- Let `y = f(x)` be the equation of a curve. The equation of the tangent at `(x_o, y_o)` is `y - y_o = m(x - x_o)`
`[(dy)/(dx)]_(x_o = y_o) = f^'(x_o)`
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?