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Let y = f(x) be the equation of a curve. Then the equation of tangent at (xo, yo) is :- -

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Question

Let y = `f(x)` be the equation of a curve. Then the equation of tangent at (xo, yo) is :- 

Options

  • `y - y_o = m(x - x_o)`

  • `y_o - y = m(x_o - x)`

  • `x_o - x = m(y - y_o)`

  • `x - x_o = m(y_o - y)`

MCQ

Solution

`y - y_o = m(x - x_o)`

Explanation:

Tangent to a Curve:- Let `y = f(x)` be the equation of a curve. The equation of the tangent at `(x_o, y_o)` is `y - y_o = m(x - x_o)`

`[(dy)/(dx)]_(x_o = y_o) = f^'(x_o)`

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