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Question
Let y = `f(x)` be the equation of a curve. Then the equation of tangent at (xo, yo) is :-
Options
`y - y_o = m(x - x_o)`
`y_o - y = m(x_o - x)`
`x_o - x = m(y - y_o)`
`x - x_o = m(y_o - y)`
MCQ
Solution
`y - y_o = m(x - x_o)`
Explanation:
Tangent to a Curve:- Let `y = f(x)` be the equation of a curve. The equation of the tangent at `(x_o, y_o)` is `y - y_o = m(x - x_o)`
`[(dy)/(dx)]_(x_o = y_o) = f^'(x_o)`
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