Question

lf y = `ae^{cos^-1x}`, then corresponding to this the differential equation is ______ 

विकल्प

• `dy/dx = (-y)/sqrt(1 - x^2)`

• `dy/dx = (-x)/sqrt(1 - x^2)`

• `dy/dx = x/sqrt(1 - x^2)`

• `dy/dx = sqrt(1 - x^2)/y`

Answer 1

lf y = `ae^{cos^-1x}`, then corresponding to this the differential equation is `underline(dy/dx = (-y)/sqrt(1 - x^2))`.

Explanation:

y = `ae^{cos^-1x}` .......(i)

⇒ `dy/dx = ae^{cos^-1x} . (-1)/sqrt(1 - x^2)`

⇒ `dy/dx = (-y)/sqrt(1 - x^2)` ....[From (i)]