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Question
lf y = `ae^{cos^-1x}`, then corresponding to this the differential equation is ______
Options
`dy/dx = (-y)/sqrt(1 - x^2)`
`dy/dx = (-x)/sqrt(1 - x^2)`
`dy/dx = x/sqrt(1 - x^2)`
`dy/dx = sqrt(1 - x^2)/y`
MCQ
Fill in the Blanks
Solution
lf y = `ae^{cos^-1x}`, then corresponding to this the differential equation is `underline(dy/dx = (-y)/sqrt(1 - x^2))`.
Explanation:
y = `ae^{cos^-1x}` .......(i)
⇒ `dy/dx = ae^{cos^-1x} . (-1)/sqrt(1 - x^2)`
⇒ `dy/dx = (-y)/sqrt(1 - x^2)` ....[From (i)]
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Solution of a Differential Equation
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