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List the important sources of sulphur - Chemistry

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प्रश्न

List the important sources of sulphur.

उत्तर १

Sulphur mainly exists in combined form in the earth’s crust primarily as sulphates [gypsum (CaSO4.2H2O), Epsom salt (MgSO4.7H2O), baryte (BaSO4)] and sulphides [(galena (PbS), zinc blends (ZnS), copper pyrites (CuFeS2)].

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उत्तर २

Sulphur mainly occurs in the combined states in earth’s crust in the form of sulphates and sulphides.
Sulphates : gypsum (CaSO4.2H2O); epsom (MgSO4.7H2O); baryte (BaSO4), etc.

Sulphides : Galena (PbS); zinc blende (ZnS); copper pyrites (CuFeS2); iron pyrites (FeS2), etc. Traces of sulphur occur’as H2S and in organic materials such as eggs, proteins, garlic, onion, mustard, hair and wool.

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अध्याय 7: The p-block Elements - Intext Questions [पृष्ठ १८३]

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एनसीईआरटी Chemistry [English] Class 12
अध्याय 7 The p-block Elements
Intext Questions | Q 13 | पृष्ठ १८३

संबंधित प्रश्न

Account for the following: Oxygen shows catenation behavior less than sulphur.


a. Explain the trends in the following properties with reference to group 16:

1 Atomic radii and ionic radii

2 Density

3 ionisation enthalpy

4 Electronegativity

b. In the electolysis of AgNO3 solution 0.7g of Ag is deposited after a certain period of time. Calulate the quantity of electricity required in coulomb. (Molar mass of Ag is 107.9g mol-1)

 


Give reasons: SO2 is reducing while TeO2 is an oxidising agent.


Give reasons for the following : H2Te is the strongest reducing agent amongst all the hydrides of Group 16 elements.


Give reasons for the following : Oxygen has less electron gain enthalpy with negative sign than sulphur.


Which of the following does not react with oxygen directly?

Zn, Ti, Pt, Fe


The HNH angle value is higher than HPH, HAsH and HSbH angles. Why? [Hint: Can be explained on the basis of sp3 hybridisation in NH3 and only s−p bonding between hydrogen and other elements of the group].


Justify the placement of O, S, Se, Te and Po in the same group of the periodic table in terms of electronic configuration, oxidation state and hydride formation.


Knowing the electron gain enthalpy values for O → O and O → O2− as −141 and 702 kJ mol−1 respectively, how can you account for the formation of a large number of oxides having O2− species and not O? (Hint: Consider lattice energy factor in the formation of compounds).


Explain why inspite of nearly the same electronegativity, oxygen forms hydrogen bonding while chlorine does not.


 Give reactions for the following: 
O – O single bond is weaker than S – S single bond. 


Arrange the following in order of the property indicated set.
HF, HCl, HBr, HI - decreasing bond enthalpy.


Which of the following statement is incorrect?


Strong reducing behaviour of \[\ce{H3PO2}\] is due to ______.


Out of \[\ce{H2O}\] and \[\ce{H2S}\], which one has higher bond angle and why?


In forming (i) \[\ce{N2 -> N^{+}2}\] and (ii) \[\ce{O2 -> O^{+}2}\]; the electrons respectively are removed from:


The correct order of ΔiHs among the following elements is


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