Advertisements
Advertisements
प्रश्न
Give reasons: SO2 is reducing while TeO2 is an oxidising agent.
उत्तर
In case of sulphur, because of the presence of empty d-orbital, it can expand its oxidation state from the + 4 to the +6 oxidation state. Hence, it acts as a reducing agent.
Te is a heavy element and so because of the inert pair effect, the lower oxidation state is more stable. Hence, it acts as an oxidising agent.
APPEARS IN
संबंधित प्रश्न
Account for the following : There is large difference between the melting and boiling points of oxygen and sulphur.
List the important sources of sulphur.
Write the order of thermal stability of the hydrides of Group 16 elements.
Knowing the electron gain enthalpy values for O → O− and O → O2− as −141 and 702 kJ mol−1 respectively, how can you account for the formation of a large number of oxides having O2− species and not O−? (Hint: Consider lattice energy factor in the formation of compounds).
Give reasons Thermal stability decreases from H2O to H2Te.
The boiling points of hydrides of group 16 are in the order:
Given below are two statements labelled as Assertion (A) and Reason (R).
Assertion (A): Electron gain enthalpy of oxygen is less than that of Flourine but greater than Nitrogen.
Reason (R): Ionisation enthalpies of the elements follow the order Nitrogen > Oxygen > Fluorine.
Select the most appropriate answer from the options given below:
The correct order of ΔiHs among the following elements is
What is the basicity of \[\ce{H3PO4}\]?
______ is a radioactive element in group 16 elements.
