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Lmnp is a Parallelogram. from the Information Given in the Figure Fill in the Following Boxes.Mn = Cmpn = Cm - Geometry Mathematics 2

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प्रश्न

LMNP is a parallelogram. From the information given in the figure fill in the following boxes.
MN = cm
PN = cm
∠ M =
∠ N =

 

उत्तर

MN = 3 cm
PN = 7 cm
∠ M = 70°
∠ N = 110°

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Centroid Formula
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2018-2019 (March) Balbharati Model Question Paper Set 1

संबंधित प्रश्न

Find the centroid of the triangle whose vertice is given below.

(–7, 6), (2, –2), (8, 5)


Find the centroid of the triangle whose vertice is given below.

 (3, –5), (4, 3), (11, –4)


Find the centroid of the triangle whose vertice is given below.

(4, 7), (8, 4), (7, 11)


In ∆ABC, G (–4, –7) is the centroid. If A (–14, –19) and B(3, 5) then find the co–ordinates of C.


A(h, –6), B(2, 3) and C(–6, k) are the co–ordinates of vertices of a triangle whose centroid is G (1, 5). Find h and k.


In the following example, can the segment joining the given point form a triangle? If a triangle is formed, state the type of the triangle considering the side of the triangle.

L(6, 4), M(–5, –3), N(–6, 8)


In the following example, can the segment joining the given point form a triangle? If triangle is formed, state the type of the triangle considering side of the triangle.

 P(–2, –6) , Q(–4, –2), R(–5, 0)


In the following example, can the segment joining the given points form a triangle? If triangle is formed, state the type of the triangle considering sides of the triangle.

A(√2, √2), B(−√2, −√2), C(−√6, √6)


Find the lengths of the medians of a triangle whose vertices are A(–1, 1), B(5, –3) and C(3, 5).


Find the coordinates of centroid of the triangles if points D(–7, 6), E(8, 5) and F(2, –2) are the mid points of the sides of that triangle.


The coordinates of the vertices of a triangle ABC are A (–7, 6), B(2, –2) and C(8, 5). Find coordinates of its centroid.

Solution: Suppose A(x1, y1) and B(x2, y2) and C(x3, y3)

 x1 = –7, y1 = 6 and x2 = 2, y2 = –2 and x3 = 8, y3 = 5

Using Centroid formula

∴ Coordinates of the centroid of a traingle

ABC = `((x_1 + x_2 + x_3)/3, (y_1 + y_2 + y_3)/3)`

= `(square/3, square/3)`

∴ Coordinates of the centroid of a triangle ABC = `(3/3, square)`

∴ Coordinates of the centroid of a triangle ABC = `(1 , square)`


The points (7, – 6), (2, k) and (h, 18) are the vertices of triangle. If (1, 5) are the coordinates of centroid, find the value of h and k


Find the centroid of the ΔABC whose vertices are A(–2, 0), B(7, –3) and C(6, 2).


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