Advertisements
Advertisements
प्रश्न
Make y the subject of formula W = `"pq" + (1)/(2)"wy"^2`
उत्तर
W = `"pq" + (1)/(2)"Wy"^2`
⇒ W - pq = `(1)/(2)"Wy"^2`
⇒ 2(W - pq) = Wy2
⇒ `(2("W" - "pq"))/"W"` = y2
⇒ Y = `sqrt((2("W" - "pq"))/"W"`.
APPEARS IN
संबंधित प्रश्न
The area A of a circular ring is π times the difference between the squares of outer radius R and inner radius r. Make a formula for this statement.
Make N the subject of formula I = `"NG"/("R" + "Ny")`
Make R2 the subject of formula R2 = 4π(R12 - R22)
Make c the subject of formula x = `(-"b" ± sqrt("b"^2 - 4"ac"))/(2"a")`
If 3ax + 2b2 = 3bx + 2a2, then express x in terms of a and b. Also, express the result in the simplest form.
Make s the subject of the formula v2 = u2 + 2as. Find s when u = 3, a = 2 and v = 5.
Make x the subject of the formula a = `1 - (2"b")/("cx" - "b")`. Find x, when a = 5, b = 12 and
Make g the subject of the formula v2 = u2 - 2gh. Find g, when v = 9.8, u = 41.5 and h = 25.4.
Make c the subject of the formula a = b(1 + ct). Find c, when a = 1100, b = 100 and t = 4.
"The volume of a cylinder V is equal to the product of π and square of radius r and the height h". Express this statement as a formula. Make r the subject formula. Find r, when V = 44cm3, π = `(22)/(7)`, h = 14cm.
