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प्रश्न
\[\ce{MnO2 + 4HCl -> MnCl2 + 2H2O + Cl2}\]
0.02 moles of pure MnO2 is heated strongly with conc. HCl. Calculate the mass of salt formed.
उत्तर
1 mole MnCl2 weighs = 55 + 2 = 126 g
So, 0.02 mole MnCl2 will weigh = 126 × 0.02 g = 2.52 g
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