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MnOA2+4HCl⟶MnClA2+2HA2O+ClA2 0.02 moles of pure MnO2 is heated strongly with conc. HCl. Calculate the mass of salt formed. - Chemistry

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Question

MnOA2+4HClMnClA2+2HA2O+ClA2

0.02 moles of pure MnO2 is heated strongly with conc. HCl. Calculate the mass of salt formed.

Numerical

Solution

1 mole MnCl2 weighs = 55 + 2 = 126 g

So, 0.02 mole MnCl2 will weigh = 126 × 0.02 g = 2.52 g

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Chapter 5: Mole concept and Stoichiometry - Exercise 5D [Page 94]

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Selina Concise Chemistry [English] Class 10 ICSE
Chapter 5 Mole concept and Stoichiometry
Exercise 5D | Q 11.3 | Page 94
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