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Question
\[\ce{MnO2 + 4HCl -> MnCl2 + 2H2O + Cl2}\]
0.02 moles of pure MnO2 is heated strongly with conc. HCl. Calculate moles of salt formed.
Solution
1 mole MnO2 gives = 1 mole of MnCl2
So, 0.02 mole MnO2will give = 0.02 mole of MnCl2
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