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Question
\[\ce{MnO2 + 4HCl -> MnCl2 + 2H2O + Cl2}\]
0.02 moles of pure MnO2 is heated strongly with conc. HCl. Calculate mass of MnO2 used.
Solution
MnO2 = Mn + 2(O)
= 55 + 2(16)
= 55 + 32
= 87 g
1 mole of MnO2 weighs = 87 g (mol. Mass)
So, 0.02 mole will weigh = 87 × 0.02 = 1.74 g
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