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Name the members of the lanthanoid series which exhibit +4 oxidation state and those which exhibit +2 oxidation state. Try to correlate this type of behavior with the electronic configurations - Chemistry

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प्रश्न

Name the members of the lanthanoid series which exhibit +4 oxidation state and those which exhibit +2 oxidation state. Try to correlate this type of behavior with the electronic configurations of these elements.

लघु उत्तरीय

उत्तर

The lanthanides that exhibit +2 and +4 states are shown in the given table. The atomic numbers of the elements are given in parentheses.

+2 +4
Nd (60) Ce (58)
Sm (62) Pr (59)
Eu (63) Nd (60)
Tm (69) Tb (65)
Yb (70) Dy (66)

After forming Ce4+, Ce attains a stable electronic configuration of [Xe].

After forming Tb4+, Tb attains a stable electronic configuration of [Xe] 4f7.

After forming Eu2+, Eu attains a stable electronic configuration of [Xe] 4f7.

After forming Yb2+, Yb attains a stable electronic configuration of [Xe] 4f14.

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अध्याय 8: The d-block and f-block Elements - Exercises [पृष्ठ २३६]

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एनसीईआरटी Chemistry [English] Class 12
अध्याय 8 The d-block and f-block Elements
Exercises | Q 32 | पृष्ठ २३६

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Explain the cause of Lanthanoids contraction.


Answer the followiiig questions: 
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Name an element of lanthanoid series which is well knwon to shown +4 oxidation state. Is it a strong oxidising agent or reducing agent? 


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a. water
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c. nitrogen, heat


Although Zr belongs to 4d and Hf belongs to 5d transition series but it is quite difficult to separate them. Why?


On the basis of Lanthanoid contraction, explain the following:

Nature of bonding in \[\ce{La2O3}\] and \[\ce{Lu2O3}\] .


On the basis of Lanthanoid contraction, explain the following:

Stability of the complexes of lanthanoids.


How would you account for the following:

There is a greater range of oxidation states among the actinoids than among the lanthanides.


Which of the following pairs has the same ionic size?


In lanthanoid the last electron enters (n - 2)f subshell where n is equal to ______.


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State a reason for the following:

La(OH)3 is more basic than Lu(OH)3.


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