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Question
Name the members of the lanthanoid series which exhibit +4 oxidation state and those which exhibit +2 oxidation state. Try to correlate this type of behavior with the electronic configurations of these elements.
Solution
The lanthanides that exhibit +2 and +4 states are shown in the given table. The atomic numbers of the elements are given in parentheses.
+2 | +4 |
Nd (60) | Ce (58) |
Sm (62) | Pr (59) |
Eu (63) | Nd (60) |
Tm (69) | Tb (65) |
Yb (70) | Dy (66) |
After forming Ce4+, Ce attains a stable electronic configuration of [Xe].
After forming Tb4+, Tb attains a stable electronic configuration of [Xe] 4f7.
After forming Eu2+, Eu attains a stable electronic configuration of [Xe] 4f7.
After forming Yb2+, Yb attains a stable electronic configuration of [Xe] 4f14.
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Column I | Column II | |
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(iii) | Most stable oxidation state of | (c) + 4 |
Mn in oxides is | (d) + 5 | |
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Column I (Property) | Column II (Element) | |
(i) | Lanthanoid which shows +4 oxidation state |
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(iii) | Radioactive lanthanoid | (c) Lu |
(iv) | Lanthanoid which has 4f7 electronic configuration in +3 oxidation state |
(d) Eu |
(v) | Lanthanoid which has 4f14 electronic configuration in +3 oxidation state |
(e) Gd |
(f) Dy |
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