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प्रश्न
On the basis of crystal field theory, write the electronic configuration for d4 ion if Δ0 > P.
उत्तर
If Δo > P, it becomes more energetically favourable for the fourth electron to occupy a t2g orbital with configuration `t_(2g)^4 e_g^0`
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संबंधित प्रश्न
How does the magnitude of Δ0 decide the actual configuration of d orbitals in a coordination entity?
Draw the structures of the following :
(1) XeF6
(2) IF7
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(i) \[\ce{[Co(H2O)6]^{2+}}\] is transformed into \[\ce{[CoCl6]}^{4-}\]
(ii) \[\ce{[Co(H2O)6]^{2+}}\] is transformed into \[\ce{[CoCl4]}^{2-}\]
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(iv) tetrahedral complexes have larger crystal field splitting than octahedral complex.
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[Ni(H2O)6]2+ (aq) is green in colour whereas [Ni(H2O)4 (en)]2+ (aq)is blue in colour, give reason in support of your answer.
In a coordination entity, the electronic configuration of the central metal ion is t2g3 eg1
Draw the crystal field splitting diagram for the above complex.
Crystal field stabilising energy for high spind4 octahedral complex is:-
On the basis of Crystal Field theory, write the electronic configuration for the d5 ion with a strong field ligand for which Δ0 > P.
On the basis of crystal field theory, write the electronic configuration for d4 with a strong field ligand for which Δ0 > P.