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Ordinary chlorine gas has two isotopes A1735A217235Cl and A1737A217237Cl in the ratio of 3 : 1. Calculate the relative atomic mass of chlorine. - Chemistry

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प्रश्न

Ordinary chlorine gas has two isotopes \[\ce{^35_17Cl}\] and \[\ce{^37_17Cl}\] in the ratio of 3 : 1. Calculate the relative atomic mass of chlorine.

संख्यात्मक

उत्तर

\[\ce{^35_17Cl : ^37_17Cl}\] = 3 : 1

∴ Total mass = (35 × 3) + (37 × 1)

= 105 + 37

= 142

∴ Relative atomic mass of chlorine = `142/4`

= 35.5

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अध्याय 5: Mole concept and Stoichiometry - Miscellaneous Exercises [पृष्ठ ९६]

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सेलिना Concise Chemistry [English] Class 10 ICSE
अध्याय 5 Mole concept and Stoichiometry
Miscellaneous Exercises | Q 14 | पृष्ठ ९६
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