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Question
Ordinary chlorine gas has two isotopes \[\ce{^35_17Cl}\] and \[\ce{^37_17Cl}\] in the ratio of 3 : 1. Calculate the relative atomic mass of chlorine.
Solution
\[\ce{^35_17Cl : ^37_17Cl}\] = 3 : 1
∴ Total mass = (35 × 3) + (37 × 1)
= 105 + 37
= 142
∴ Relative atomic mass of chlorine = `142/4`
= 35.5
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