हिंदी

(P) C6H5N=CH-C6H5 is a Schiff's base. (Q) A dye is obtained by the reaction of aniline and C6H5N=NCl. (R) C6H5CH2NH2 on treatment with [NaNO2 + HCl] gives diazonium salt. -

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प्रश्न

Which of the following statements are correct:

(P) C6H5N=CH-C6H5 is a Schiff’s base.

(Q) A dye is obtained by the reaction of aniline and C6H5N=NCl.

(R) C6H5CH2NH2 on treatment with [NaNO2 + HCl] gives diazonium salt.

(S) p-Toluidine on treatment with [HNO2 + HCl] gives diazonium salt.

विकल्प

  • Only (P) and (Q) are correct.

  • Only (P) and (R) are correct.

  • Only (R) and (S) are correct.

  • (P), (Q) and (S) are correct.

MCQ

उत्तर

(P), (Q) and (S) are correct.

Explanation:

(P) C6H5N=CH–C6H5 is a Schiff’s base.

(Q)


(R) \[\ce{C6H5CH2NH2 ->[NaNO2 + HCl] \underset{Benzyl alcohol not a diazonium salt}{C6H5CH2-OH}}\]

(S)

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