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प्रश्न
Which of the following statements are correct:
(P) C6H5N=CH-C6H5 is a Schiff’s base.
(Q) A dye is obtained by the reaction of aniline and C6H5N=NCl.
(R) C6H5CH2NH2 on treatment with [NaNO2 + HCl] gives diazonium salt.
(S) p-Toluidine on treatment with [HNO2 + HCl] gives diazonium salt.
विकल्प
Only (P) and (Q) are correct.
Only (P) and (R) are correct.
Only (R) and (S) are correct.
(P), (Q) and (S) are correct.
MCQ
उत्तर
(P), (Q) and (S) are correct.
Explanation:
(P) C6H5N=CH–C6H5 is a Schiff’s base.
(Q)
(R) \[\ce{C6H5CH2NH2 ->[NaNO2 + HCl] \underset{Benzyl alcohol not a diazonium salt}{C6H5CH2-OH}}\]
(S)
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