Question

Which of the following statements are correct:

(P) C₆H₅N=CH-C₆H₅ is a Schiff’s base.

(Q) A dye is obtained by the reaction of aniline and C₆H₅N=NCl.

(R) C₆H₅CH₂NH₂ on treatment with [NaNO₂ + HCl] gives diazonium salt.

(S) p-Toluidine on treatment with [HNO₂ + HCl] gives diazonium salt.

Options

• Only (P) and (Q) are correct.

• Only (P) and (R) are correct.

• Only (R) and (S) are correct.

• (P), (Q) and (S) are correct.

Answer 1

(P), (Q) and (S) are correct.

Explanation:

(P) C₆H₅N=CH–C₆H₅ is a Schiff’s base.

(Q)

(R) \[\ce{C6H5CH2NH2 ->[NaNO2 + HCl] \underset{Benzyl alcohol not a diazonium salt}{C6H5CH2-OH}}\]

(S)