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प्रश्न
P , Q and R are collinear points such that PQ = QR . IF the coordinates of P , Q and R are (-5 , x) , (y , 7) , (1 , -3) respectively, find the values of x and y.
उत्तर
Given PQ = PR , i.e. PQ : QR = 1 : 1
Coordinates of Q are ,
Q (y , 7) = Q `((1 - 5)/2 , (-3 + "x")/2)`
y = -2 , 7 = `(- 3 + "x")/2`
y = -2 , 14 = - 3 + x
17 = x
The value of x and y are 17 and -2 respectively.
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संबंधित प्रश्न
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The ratio in which the x-axis divides the line segment joining the points A (a1, b1) and B (a2, b2) is
Find coordinates of the midpoint of a segment joining point A(–1, 1) and point B(5, –7)
Solution: Suppose A(x1, y1) and B(x2, y2)
x1 = –1, y1 = 1 and x2 = 5, y2 = –7
Using midpoint formula,
∴ Coordinates of midpoint of segment AB
= `((x_1 + x_2)/2, (y_1+ y_2)/2)`
= `(square/2, square/2)`
∴ Coordinates of the midpoint = `(4/2, square/2)`
∴ Coordinates of the midpoint = `(2, square)`
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