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प्रश्न
Pb has fcc structure with edge length of unit cell 495 pm. Radius of Pb atom is ______.
विकल्प
205 pm
185 pm
260 pm
175 pm
MCQ
रिक्त स्थान भरें
उत्तर
Pb has fcc structure with edge length of unit cell 495 pm. Radius of Pb atom is 175 pm.
Explanation:
Given: a = 495 pm
Radius, r = ?
For fee structure
radius = r = `a/(2sqrt2) = 495/(2sqrt2) = 175` cm
The radius of the Cu atom = is 175 pm.
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