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प्रश्न
Pb has fcc structure with edge length of unit cell 495 pm. Radius of Pb atom is ______.
पर्याय
205 pm
185 pm
260 pm
175 pm
MCQ
रिकाम्या जागा भरा
उत्तर
Pb has fcc structure with edge length of unit cell 495 pm. Radius of Pb atom is 175 pm.
Explanation:
Given: a = 495 pm
Radius, r = ?
For fee structure
radius = r = `a/(2sqrt2) = 495/(2sqrt2) = 175` cm
The radius of the Cu atom = is 175 pm.
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