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प्रश्न
Potassium (at No.19) and chlorine (at No.17) react to form a compound. Explain the formation of the compound on the basis of reduction.
उत्तर
\[\ce{2K + Cl2 -> 2KCl}\]
In the electronic concept, a reduction is a process in which an atom or ion accepts electron(s).
\[\ce{Cl2 + 2e--> 2Cl-}\]
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संबंधित प्रश्न
Match the atomic number 4, 8, 14, 15 and 19 with each of the following:
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(c) A metal of valency 1.
(d) A non-metal of valency 4
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Match the atomic numbers 4, 14, 8, 15 and 19 with each of the following:
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- A gas of valency 2.
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An element having valency 'zero'
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Complete the table give below.
| Element |
Atomic number |
Electron distribution | Valence electrons | Lewis dot structure |
| Lithium | 3 | 1s22s1 | ||
| Boron | 5 | 1s22s22p1 | ||
| Oxygen | 8 | 1s22s22p4 |
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In the formation of compounds, the inner shell electrons of an atom involved in bonding.
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| 1. | Monoatomic gaseous atom | a. | Electrovalent bond |
| 2. | Octet rule | b. | Benzene |
| 3. | Ionic bond | c. | Water |
| 4. | Non-polar solvent | d. | Electronic theory of valence |
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| a. | Dativebond | ______ |
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| d. | ______ | Redox reaction |
