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प्रश्न
ΔPQR is isosceles with PQ = PR. T is the mid-point of QR, and TM and TN are perpendiculars on PR and PQ respectively. Prove that,
PT is the bisector of ∠P.
योग
उत्तर
In ΔPNT and ΔPMT
TN = TM ...(proved)
PT = PT ...(common)
∠PNT = ∠PMT ...(90°)
Therefore, ΔPNT ≅ ΔPMT
Hence, ∠NPT = ∠MPT
Thus, PT bisects ∠P.
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