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Predict the major product (s) of the following reactions and explain their formation. HX3C−CH=CHX2→HBr(Ph⋅CO⋅O)X2 HX3C−CH=CHX2→HBr - Chemistry

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प्रश्न

Predict the major product (s) of the following reactions and explain their formation.

\[\ce{H3C - CH = CH2 ->[(Ph.CO.O)2][HBr]}\]

\[\ce{H3C - CH = CH2 ->[HBr]}\]

टिप्पणी लिखिए

उत्तर

Addition of HBr to unsymmetrical alkenes follows Markonikov rule. It states that negative part of the addendum (adding molecule) gets attached to that carbon atom which possesses lesser number of hydrogen atoms.

Mechanism: Hydrogen bromide provides an electrophile, H+, which attacks the double bond to form carbocation as shown below:

The (b) is attacked by Br ion to form the product as follows:


Addition reaction of HBr to unsymmetrical alkenes in the presence of peroxide follows anti-Markovnikov rule.
Mechanism: Peroxide effect proceeds via free radical chain mechanism as given below:

(i) 

(ii) \[\ce{\overset{\bullet}{C6}H5 + H - Br ->[Homolysis] C6H6 + \overset{\bullet}{B}r}\]

(iii)

(iv) \[\ce{CH3 - \overset{\bullet}{C}H - CH2Br + H - Br ->[Homolysis] \underset{(major product)}{CH3 - CH2 - CH2Br + Br}}\]

\[\ce{H3C - CH = CH2 ->[(PhCOO)2][HBr] \underset{(Anti-Markovnikov addition)}{H3CCH2CH2Br}}\]

\[\begin{array}{cc}
\ce{H3C - CH = CH2 ->[HBr] H3C - CH - CH3}\\
\phantom{......................}|\\
\phantom{.......................}\ce{\underset{(Markovnikov addition)}{Br}}
\end{array}\]

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 13: Hydrocarbons - Multiple Choice Questions (Type - I) [पृष्ठ १६६]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
अध्याय 13 Hydrocarbons
Multiple Choice Questions (Type - I) | Q 31 | पृष्ठ १६६
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