Advertisements
Advertisements
प्रश्न
Product of 6a2 – 7b + 5ab and 2ab is ______.
विकल्प
12a3b – 14ab2 + 10ab
12a3b – 14ab2 + 10a2b2
6a2 – 7b + 7ab
12a2b – 7ab2 + 10ab
उत्तर
Product of 6a2 – 7b + 5ab and 2ab is 12a3b – 14ab2 + 10a2b2.
Explanation:
Required product = 2ab × (6a2 – 7b + 5ab)
This is the product of a trinomial by a monomial, so we multiply monomial with each term of the trinomial.
∴ 2ab × (6a2 – 7b + 5ab) = 2ab × 6a2 + 2ab(–7b) + 2ab × 5ab
= 12a3b – 14ab2 + 10a2b2
APPEARS IN
संबंधित प्रश्न
Simplify.
(t + s2) (t2 − s)
Simplify.
(x + y) (x2 − xy + y2)
Simplify.
(1.5x − 4y) (1.5x + 4y + 3) − 4.5x + 12y
Simplify.
(a + b + c) (a + b − c)
Write the following square of binomial as trinomial: \[\left( 9a + \frac{1}{6} \right)^2\]
Write the following square of binomial as trinomial: \[\left( \frac{x}{4} - \frac{y}{3} \right)\]
Write the following square of binomial as trinomial: (a2b − bc2)2
p2q + q2r + r2q is a binomial.
Multiply the following:
–7st, –1, –13st2
Multiply the following:
`- 100/9 rs; 3/4 r^3s^2`